Question

Which of the following points is in the solution set of y < x2 - 2x - 8?
(-2, -1)
(0, -2)
(4, 0)

Answer 1

please answer i need help!!!!

Answer 2

-1<4+4-8=0
-1<0 true, so first point is good.
repeat the same for other 2 points

Answer 3

-2<0^2-0-8=-8
-2<-8 is not a true statement , so second point is not a solution

Answer 4

0<4^2-2*4-8=16-8-8=0
0<0 is not a true statement , should be 0=0
so your only solution is point: (-2, -1)