Question

how can i find th domain for this?
y=1/(6 x^2 +3 x + 16)
thanks guys!

Answer 1

the domain is all real numbers except what makes the denominator 0.

Answer 2

nothing makes it 0, so the domain is all real numbers

Answer 3

the roots dont make it 0?

Answer 4

such as a problem like y=(x- 6)/(x^2- 7 x + 6)

Answer 5

there were no real roots for the denominator
(x-6)(x-1) so all real numbers except 1,6

Answer 6

ohhh ok that totally makes sense now, since it was a negative in the square root! thanks ur awesome!