Question

A curve has eq. y=(x²-3)e^-x.
Find the coordinates of the pts. of intersection of the curve with the x-axis.

Answer 1

Set it equal to zero. e^-x is never zero. So you only need to worry about x^2-3
Which gives you +sqrt(3) and -sqrt(3)

Answer 2

Oh. Ok thanks! :)

Answer 3

No problem :P