Question

Solve (4x^2-4x+1) / (8x^3-1)

Answer 1

what does "solve" mean in this case?

Answer 2

Divide

Answer 3

note that 4x^2-4x+1 = (2x-1)^2
and 8x^3 -1 = ((2x)^3 - 1^3)

Answer 4

in other words factor the numerator and denominator and cancel. numerators i s
\[(2x-1)(2x-1)\] denominator os
\[(2x-1)(4x^2+2x+1)\]

Answer 5

giving
\[\frac{2x-+1}{4x^2+2x+1}\]