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OpenStudy (anonymous):
A 0.1-kg object is traveling to the right (in the positive direction) with a speed of 3 m/s. After a 0.2 s collision, the object is traveling to the left at 3 m/s. What is the magnitude of the impulse (in N-s) acting on the object?
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OpenStudy (anonymous):
Impulse = change in momentum = m(vf - vi) = 0.1kg(-3m/s - 3 m/s) = -0.6N-s
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