Question

If AM = 8, AB = 16, and CD = 20, and if AM is shorter than CM, find CM.

hellllp

Answer 1

AM * MB = CM * MD

8(16-8) = (20-x)x

64 = 20x-x^2

x^2 -20x +64 = 0

1,64; 2,32; 4,16 .....

(x-16) (x-4) = 0; x=16, or x=4

Since AM{8} is shorter than CM; we have to pick:

8 < CM ... 8 < 16; CM = 16