Question

Solve x2 + 8x + 8 = 0 by completing the square.

Answer 1

the array is just fun to make lol :)

\begin{array}c
x^2&x&x&x&x\\
x&1&2&3&4\\
x&5&6&7&8\\
x&9&10&11&12\\
x&13&14&15&16\\
\end{array}

gotta add and subtract 16 to it :)

Answer 2

x^2+8x +(16-16) +8 = 0

(x^2 +8x +16) + (-16+8) = 0

(x+4)^2 - 8 = 0

(x+4)^2 = 8 ; we need sqrt(8) so get rid of that 4 in there

-4 +- sqrt(8) ; which can be simplified to:

-4 +- 2sqrt(2)

Answer 3

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