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If CM = 8, DM = 6, and AB = 16, and if AM is longer than DM, find AM.
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\[(AB)(AM)=(CM)(MD)\] let AM be equal to x+6 \[(16)(x+6)=(14)(6)\] \[x+6=84/16\]\[x+6=5.25\]\[x=5.25-6----------=-0.75\]since AM =x+6\[AM=-0.75+6\]\[AM=5.25\]
dou know whatgoes into 18 cus idid 6x3 = 18 but then i had to divide by anumber i tried 2 but that didnt work
what of 9 and 2
no of 6 and 3
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