Question

The radius of the base of a cylinder is 28 cm and its height is 48 cm. Find the surface area of the cylinder is terms of pi.

Answer 1

2π(28)(28+48) = 56π(76) = 4256π

Answer 2

area of the bases
\[2\pi r ^{2}=2\pi * 784=1568\pi\]
circumference of base \[2\pi r = 56\pi\]
extension of the height
\[2\pi r*h=56\pi*48=2688\pi\]
bases plus none base surface is total surface
\[1568\pi + 2688\pi = 4256\pi\]

Answer 3

Surface Area of cylinder = 2πr (r+h)

where r = radius of base
h = height of cylinder