Which of the following systems of equations has no solution?
1) 8x - 6y = 14; 3y = 4x - 7
2) 6x - 4 = 3y; 6y - 1 = 12x
3) 9x - y = 12; 2y = 18x - 24
4) -5y = x - 8; 2x - 10y = 7

Question

amistre64 · Answer

the ones that are seperate but parallel lines

amistre64 · Answer

look for the 2 that have the same equations; but a different "equals number"

amistre64 · Answer

arrange them so they are both in the same form

8x - 6y = 14       3y = 4x - 7

8x - 6y = 14       -4x + 3y = - 7 [*-2]

8x - 6y = 14       8x -6y = 14 ; these are the same lines

anonymous · Answer

just use destroying method ...

amistre64 · Answer

6x - 4 = 3y       6y - 1 = 12x

6x -3y = 4 [-2]  -12x + 6y  = 1 

-12x +6y = -8   -12x + 6y  = 1 ; that looks like a winner