Question

hey redrum for some reason i cannot open your post. but if sinx=1/3 then cosx=sqrt{8}/3
and since it is in Q2 we should say cosx=-sqrt{8}/3

Answer 1

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Answer 2

i drew a right triangle i wias giving two sides of the triangle the opposite(=1) of the angle x and the hypothnues(=3). I used the pythagorean thm to find the adjacent of angle x which was sqrt{8}
now you can draw this traingle on the cartesian coordinate thingy but you must draw the triangle in the Q2 since that is what the directions say so that means the base (the adjacent of angle x) is going to be sqrt{8}

Answer 3

-sqrt{8}*

Answer 4

can anyone else open his post?

Answer 5

http://openstudy.com/groups/mathematics/updates/4e0b8b750b8bd74af49d6fe8#/groups/mathematics/updates/4e0b8b750b8bd74af49d6fe8

Answer 6

thanks amistre but i think he left already :(