Question

What is the solution set of (x - 2)(x - 3) = 2

Answer 1

expand first \[x^2-3x-2x+6=2\]\[x^2-5x+6=2\]

Answer 2

\[x^2-5x+6-2=0\]\[x^2-5x+4=0\]solve using the quadratic formula\[-b \pm \sqrt{b^2-4*a*c}\]--------------------\[ 2a\]

Answer 3

(x-4)(x-1)=0
x=4
x=1