Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (anonymous):

Find: dy/dx 1/(sq. rt. x+1)

OpenStudy (anonymous):

using the quotient rule: u = 1 v = sq. rt. x+1 u' = 0 v' = 1/2(x+1)^-1/2

OpenStudy (anonymous):

try the chain rule

OpenStudy (anonymous):

ah okay

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!