Question

Solve:
2^(3x-1)=5

Answer 1

take the logarithm of both sides:

log(2^(3x-1)) = log(5)

thus (3x - 1)*log(2) = log(5)

thus 3x - 1 = log(5)/log(2)

thus x = 1/3((log(5)/log(2)) + 1)