Question

if (3x^2)+7=0 then (x-1/3)^2 how do you suppose to solve this problem?

Answer 1

is the 3 under x-1? or under 1 only?

Answer 2

x^2=-7/3 ..... (1)
(x-1/3)^2=x^2-2/3x+1/9=
from (1)
we get
\[-7/3-2/3\sqrt{7/3}i +1/9\]
\[=-20/9-2/3\sqrt{7/3}i\]
whic i=imajiner