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Mathematics 15 Online
OpenStudy (anonymous):

prove that tan@tan(60-@)tan(60+@)=tan3@. here"@" is taken as "theta".

OpenStudy (anonymous):

\[\tan(60-t)\tan(60+t) = (\sqrt3 - tant)(\sqrt3 + tant)/(1 + \sqrt3 tant)(1- \sqrt3 tant)\]

OpenStudy (anonymous):

\[= (3 - \tan^{2} t)/ (1 - 3\tan^{2}t)\]

OpenStudy (anonymous):

now multiply that by tan t u get \[(3tant - \tan ^{3} t)/ (1 - 3\tan^{2} t) \ which \ is \ equal \ t o \ \tan 3t\]

OpenStudy (anonymous):

thxx

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