Question

Give the excluded value(s) for the following fraction.

y+5/y^2+4y-32

Answer 1

you can't divide by 0, which is means that denominator can not be =0
solve:
y^2+4y-32=0
find y - those values are excluded
can you finish it?

Answer 2

no

Answer 3

y^2+4y-32=(y+8)*(y-4)=0
how about now?

Answer 4

i havent even learned how to do this

Answer 5

if a*b=0 then a=0 or b=0... right?
so from the above:
y+8=0 or y-4=0
so
y=...?

Answer 6

8,-4

Answer 7

y=-8 and y=4 are excluded
(you forgot to change the sign...)