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Mathematics 14 Online
OpenStudy (anonymous):

The average hourly wage of employees of a certain company is $9.83. Assume the variable is normally distributed. If the standard deviation is $4.58, find the probability that a randomly selected employee earns less than $5.43

OpenStudy (amistre64):

mean = 9.83 sd = 4.58 limits = -9999, 5.43 -9.83 5.43 ------ -4.40/4.48 = -.98514 .... as a z-score but really; just ti83 it :)

OpenStudy (amistre64):

.16835....

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