Question

The average hourly wage of employees of a certain company is $9.83. Assume the variable is normally distributed. If the standard deviation is $4.58, find the probability that a randomly selected employee earns less than $5.43

Answer 1

mean = 9.83
sd = 4.58

limits = -9999, 5.43

-9.83
5.43
------
-4.40/4.48 = -.98514 .... as a z-score

but really; just ti83 it :)

Answer 2

.16835....