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x= t^2 + 2t y= 2t^3 - 6t get dy/dx when t = 0, 2, 5
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find dy/dt, dx/dt dy/dt * dt/dx to find dy/dx
dx/dt= 2t+2 dy/dt=6t^2 -6
(6t^2-6)/(2t+2)
plug in number
i already have my own solution. i just need to verify if i did it right.
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at 0 -> -3 at 2 -> 3 at 5 -> 12
yes. i got it right. thanks for verifying it. :)
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