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F(x)= (2x)^sinx
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what are we doing with the function?
finding the first derivative
which i believe looks like this: \[f(x) = (2x)^{sinx}\] right?
correct
alright, im going to write out a solution and post it, its faster for me lol, one sec
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ok thanks
here ya go :)
If you need anything clarified just let me know
i agree i took a different approach but its right
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