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Mathematics 19 Online
OpenStudy (anonymous):

F(x)= (2x)^sinx

OpenStudy (anonymous):

what are we doing with the function?

OpenStudy (anonymous):

finding the first derivative

OpenStudy (anonymous):

which i believe looks like this: \[f(x) = (2x)^{sinx}\] right?

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

alright, im going to write out a solution and post it, its faster for me lol, one sec

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

here ya go :)

OpenStudy (anonymous):

If you need anything clarified just let me know

OpenStudy (anonymous):

i agree i took a different approach but its right

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