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Mathematics 21 Online
OpenStudy (anonymous):

from k=1 to infinity, converging or diverging (k(k+2))/(k+3)^2

OpenStudy (anonymous):

The numerator and denominator are of the same degree - the integral \[\int\limits_{1}^{\infty} x(x+2)/(x+3)^2 dx \] Will diverge, and thus so will the series in question

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