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Mathematics 11 Online
OpenStudy (anonymous):

hardest one yet. find y' of the function x^y=y^x

OpenStudy (bahrom7893):

WOOHOO!! this is kickass yLnx=xLny

OpenStudy (bahrom7893):

y*(1/x) + y'(Lnx) = x*(1/y)*y'+x*Lny

myininaya (myininaya):

OpenStudy (bahrom7893):

okay myininaya got this..

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