Ok, I just got back from a hike up the side of a mountain. Here is the data from my GPS:

Change in altitude +47m
Displacement to the north +204m
Displacement to the west +2m
Traveling time 2 minutes, 46 seconds

How steep was the hill? (in degrees)
How fast did I travel? (in km/h)

Question

Ok, I just got back from a hike up the side of a mountain. Here is the data from my GPS:

Change in altitude +47m
Displacement to the north +204m
Displacement to the west +2m
Traveling time 2 minutes, 46 seconds

How steep was the hill? (in degrees)
How fast did I travel? (in  km/h)

llort · Answer

since no one else is answering, I will do this myself...

The distance traveled is:

$$\sqrt{204^2+2^2+47+2}\approx209.35375$$

with the Trig, I have:

$$\sin (47/209.35375)\approx0.22261932$$

The question is what is that in degrees?

Also, it is 4.540202 km/h

Was that so hard?

llort · Answer

IDK where that +2 at the end of the equation came it, it's wrong... :S