Question

Find n(12):

1, 2, 4, 7, 12, 20, 33, 54, 88

Answer 1

the differences are fibonaccied

Answer 2

terms in crease by 1 2 3 5 8 13 21 34 so next increments 55 89 144
the next one is the sum of previous two

so n 12 = 88 + 55 + 89 + 144 = 376

Answer 3

subtracting each by predecessor gives you this sequence:
1, 2, 3, 5, 8, 13, 21, 34...
which is the Febunacci sequence
... 55, 89, 144, 223, 377
then just use this sequence to add each time to the next number...
88+55=143
143+89=232
232+144=376

so the n(12)=376