Question

HELP

Answer 1

R.E.S.C.U.E.

Answer 2

xD

Answer 3

Find derivative of the function= f'(x)
plug each of the point in to f'(x)

Answer 4

f'(x)=\[\frac{-\sqrt{3} \text{Cos}[x]^2-2 \text{Sin}[x]-\sqrt{3} \text{Sin}[x]^2}{\left(2+\sqrt{3} \text{Sin}[x]\right)^2}\]

Answer 5

if you plug in point into f'(x) and get 0 then it is horizontal

Answer 6

\[f'\left[\frac{2\pi }{3}+2\pi \right]\]=\[-\frac{8 \sqrt{3}}{49}\]

\[f'\left[\frac{4\pi }{3}+2\pi \right]\]=0
So that's it

Answer 7

What part do you have question?