Question

the perimeter of a rectangle is 176 inches the length exceeds the width by 8 inches find the length and width

answer must be a decimal

Answer 1

\[length = width + 8\]\[perimeter = 2*length + 2*width\]\[perimeter = 2 * (width + 8) + 2* width\]\[perimeter = 4*width + 16 = 176\]\[4*width = 160\]\[width = 40\]\[length = 48\]

Answer 2

176=(L+W)2
176/2=L+W L+W=88
L= 8+W
8+W+W=88
2W=88-8
W=80/2
W=40
L+40=88
L=88-40
L=48