the perimeter of a rectangle is 176 inches the length exceeds the width by 8 inches find the length and width

answer must be a decimal

Question

the perimeter of a rectangle is 176 inches the length exceeds the width by 8 inches find the length and width

answer must be a decimal

anonymous · Answer

$$length = width + 8$$$$perimeter = 2*length + 2*width$$$$perimeter = 2 * (width + 8) + 2* width$$$$perimeter = 4*width + 16 = 176$$$$4*width = 160$$$$width = 40$$$$length = 48$$

anonymous · Answer

176=(L+W)2
176/2=L+W           L+W=88
L= 8+W
 8+W+W=88
        2W=88-8
          W=80/2
          W=40
L+40=88
       L=88-40
       L=48