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-14≤4x-3≤-2 solve
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v will sovle them seperately.
First this: -14≤4x-3 -14 + 3 ≤ 4x -11 ≤ 4x -11/4 ≤ x
then this: 4x-3≤-2 4x ≤ 1 x ≤ 1/4
-11/4 ≤ x ≤1/4
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When it's connected I just solve the simultaneously.. \(-14\le4x-3\le-2\)\[\implies -14 + 3 \le 4x \le -2 + 3\]\[\implies -11 \le 4x \le 1\]\[\implies -\frac{11}{4} \le x \le \frac{1}{4}\]
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