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OpenStudy (anonymous):
Find values of k so that each remainder is 3
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OpenStudy (anonymous):
\[(x^2+5x+7)\div(x+k)\]
OpenStudy (callisto):
hmm.. By remainder thm, Put x=-k \[(-k)^{2}+5(-k)+7 = 3\]\[k ^{2}-5k+4 =0\]k=4 or k=1
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