Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

p^3 * p^2 * p

OpenStudy (callisto):

p^6

OpenStudy (anonymous):

=p^3*p^2*p^1=p^5

OpenStudy (anonymous):

6 i mean sory

OpenStudy (anonymous):

lol

OpenStudy (callisto):

\[p ^{3}*p ^{2}*p= p ^{3+2+1}=p ^{6}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!