Question

completely factor the expression by grouping:
d^2-du-5d+5u

Answer 1

d^2-du-5d+5u = d[d-u]-5[d-u]

= (d-u)(d-5)

Answer 2

think of d^2 =dxd , 5d= 5xd, du=dxu and 5u=5xu then put them together
d^2-du-5d+5u=(d-5)(d-u)

Answer 3

or d^2-du-5d+5u=d(d-5)-u(d-5)=(d-5)(d-u)

Answer 4

hope you get a better understanding of how i do it kelly..

Answer 5

Thanks a bunch!!!

Answer 6

ywc..have fun..lol