Question

Solve this system of equations using substitution. Put your answer in ordered pair form, (x, y).
x + y = 15
4x + 3y = 38

Answer 1

x = 15-y
4(15-y)+3y=38
60-4y+3y =38
60-y=38
60-38 = y
22 = y
x+22 = 15
x= 15-22
x=-7

Answer 2

i dont understand

Answer 3

x + y = 15
x +y-y = 15-y
x = 15-y

4x+3y=38
4(15-y)+3y=38
60-4y+3y=38
60-y=38
60-y-38=0
60-y-38+y=y
22 = y

x+y = 15
x+22=15
x+22-22 = 15-22
x = 7

Answer 4

is the (7,22) the answer?

Answer 5

yes

Answer 6

15-22 = -7 sry

Answer 7

x+y = 15 (Equation 1)
4x +3y = 38 (Equation 2)

Rearange Equation 1 to make it equation to x

x = 15 - y, we shall call this Equation 3.

We Substitute Equation 3, into Equation 2.
This means we the x values in Equation 2, with the values x is equal to in Equation 3.

Hence,

4 (15 - y) + 3y = 38
Expanding we get,

60 - 4y + 3y = 38
Simplifying,

-y = - 22
Making this positive you get

y = 22

Now we have a value for y, we can simply subsitute this into another Equation, I reccomend Equation 3.

y = 22

x= 15 -y

Subsituting our value for y

x = 15 -22

x = -7

In the form you ask, (-7, 22)

Hope this helps :)