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Two planes which are 2265 miles a apart, fly toward each other. Their speed differs by 55 mph. If they pass each other in 3 hours, what is the speed of each?
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use relative velocity
let their speeds be v1 and v2 Relative speed(or frame of reference); Assume one plane to be at rest, then the speed of other will become (v1+v2) v2-v1=55.......(1) Given so, v2=v1+55 so, (v1+v2)= v2+v2+55 = 2.v2+55 Now, distance/speed = time 2265/(2v2+55) = 3 hence v2 and v1
v2=350 mph v1=295 mph
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