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Mathematics 8 Online
OpenStudy (anonymous):

A=h/2 (a+b) solve for h

OpenStudy (saifoo.khan):

h = (2A)/ (a+b)

OpenStudy (saifoo.khan):

is it like: A = (h/2) (a+b) ??

OpenStudy (anonymous):

h over 2

OpenStudy (llort):

does A=a?

OpenStudy (saifoo.khan):

Im correct then.

OpenStudy (anonymous):

\[A=\frac{h}{2}(a+b)\]2A=h(a+b)\[h=\frac{2A}{a+b}\]

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