Question

how to print upto a specified value in a charecter array in c??

Answer 1

as in how to print an array of characters until a given character? Do you know it's position in the array or are you essentially asking for a searching algorithm?

Answer 2

for(i=0;array[i]!='character';i++);

character here could be any of the alphabets

Answer 3

can't put the ; before the print command.

Answer 4

simple example for reading a character & printing those...
char a[10];
for(i=0;i<10;i++)
scanf("%c",a[i]);
for(i=0;i<10;i++)
printf("entered chars. are %c \n",a[i]);

Answer 5

You would probably want to include string.h. My method:

#include <stdio.h>
#include <string.h>

int main(int argc, char* argv[]){
const char *stopcondition = "put char to stop on here";
char *mystring = "Here's the char array to be searched.";
char *c = mystring;
while (*c){
if (strchr(stopcondition, *c))
printf("%c is in \"%s\"\n", *c, mystring);
c++;}
return 0;
}

Answer 6

#include<stdio.h>
int main()
{
int i;
char ch[5];
ch[0]='a';
ch[1]='v';
ch[2]='b';
ch[3]='n';
ch[4]='e';
int limit=sizeof(ch); //takes the size of array
for(i=0;i<limit;i++) // loops upto the size of array and print its all element
{
printf("%c \n",ch[i]);
}
getch();
return 0;
}