Question

25y^2=75y+100

Answer 1

25y^2-75y-100=0

25(y^2-3y-4)=0

what ads to -3 and multiplies to -4?

Answer 2

25(y - 4)(y + ? )

what number replaces the ?

Answer 3

any idea kia?

Answer 4

continuing from mine...

a+b=-3
a*b=-4

-4+1=-3
-4*1=-4

so it is:

25(x-4)(x+1)=0

Answer 5

the second number in each bracket multiplied together must equal -4

Answer 6

25(y*2 -3y -4)=0
3 +/- radical (9+16) 3 +/- 5
y_1,_2= ----------------- = -------- = -1 and 4
2 2

y_1 = -1
y_2 = 4