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Employees use two methods to refinish tables. Method I takes 0.5 hours and the material costs $8. Method II takes 1.5 hours, and the material costs $4. Next week, they plan to spend 91 hours in labor and $896 in material for refinishing tables. How many tables should they plan to refinish with each method? (round to two decimal places if necessary)
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0.5x+1.5y=91 8x+4y=896 x...mehod I and y...method II
I dont understand how to solve this
use elimination method to find the values of x and y
multiply first eqn by 8,second by 0.5 and subtract, x is cancelled out 12y=728 2y=448 -------- 10y=280 y=28
x=98
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