Question

1/9x^2+11/3x=60

Answer 1

same idea as before yes? put
\[z=\frac{1}{3x}\] and solve
\[z^2+11z-60=0\]
\[(z-4)(z+15)=0\]
\[z=4\] or \[z=-15\]

Answer 2

\[\frac{1}{3x}=4\]
\[x=\frac{1}{12}\]
\[\frac{1}{3x}=-15\]
\[x=-\frac{1}{45}\]