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Solve |2x-2|<8 i got {x|x<-3 or x>5} is that right?
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no this one has one interval
this is how you can tell: if you have \[|blah|>p\] TWO intervals if you have \[|blah|<p\] you have ONE interval
so if you see \[|2x+2|<8\] you solve \[-8<2x-2<8\]
whereas if you have \[|2x-2|>8\] you need to solve \[2x-2<-8\] or \[2x-2>8\]
{x|-5<x<3}
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?
it all depends on the direction of the inequality. that is how you can tell. but don't forget that if you know one, then you know the other. \[|2x-2|<8\] \[-8<2x-2<8\] \[-6<2x<10\] \[-3<x<5\]
steps were a) add 2 all the way across b) divide by 2 all the way across
i think you subtracted 2 when you should have added 2 yes?
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