Question

how would i solve this?
The sum of 3 consecutive integral numbers is 117. Find the numbers.

Answer 1

x+(x+1)+(x+2)=117

Answer 2

x+(x+1)+(x+2)=117

Answer 3

n+(n+1)+(n+2)=117 (where n is the smallest integer)
n+n+1+n+2=117
3n+3=117
3n=114
n= 38
the numbers are 38, 39, and 40

Answer 4

n+(n+1)+(n+2)=117 so n= 38