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factor by grouping. x^3+8x^2-2x-16
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group first two term and then next two terms first two term have x^2 in common x^2(x+8) next two term have -2 in common -2(x+8) x^2(x+8)-2(x+8)
(x^3+8x^2)-(2x+16) x^2(x+8)-2(x+8) (x^2-2)(x+8) (x-sqrt{2})(x+sqrt{2})(x+8)
both term have (x-8) in common so (x^2 -2) (x+8)
Hi, usingfactoring by grouping, solve 6x^3-6x^2-x+1
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