Question

The length of a rectangle is 2 more than twice the width. Find the dimensions of the rectangle if the perimeter is 76.

If x represents the width of the rectangle, then which expression represents the perimeter?
would the answer be:
4x + 4?

Answer 1

If x is the width, the length is 2x+2 (two more than twice the width). if the perimeter is 76 units, then:

2L + 2W = 76
2(2x+2) + 2x = 76
6x+4=76
x = 12

The width is 12 units and the length is 2(12)+2=26 units
CHECK: 2(12)+2(26)=76 units :)