Question

a point P(x,y) lies on the curve y=sqrt x
express the perimeter of a shaded triangle as a function of x.

Answer 1

assuming a point iof the triangle is the origin

Answer 2

x+sqrtx+sqrt(x^2+x)

Answer 3

\[P = x + \sqrt{x}+ \sqrt{x^2 +x} \]

Answer 4

Thank you!

Answer 5

Can you tell me what the Area is for the same question?