Question

A real number x1, such that f(x1)=0, is said to be a real root of the equation f(x)=0. show that there is a root for equation:
sin(x)=x^2-x for 1 14 years ago

Answer 1

test

Answer 2

Find some a such that 1 < a < 2 where f(a) < 0, and find a b such that 1 < b < 2 where f(b) > 0. There must then be some c between a and b such that f(c) = 0.