Ask
your own question, for FREE!
Mathematics
5 Online
\[Q_{\alpha}(f) = \lambda_{(\alpha,1)} f(0) + \lambda_{(\alpha,2)} f(\alpha) +\lambda_{(\alpha,3)} f(1)\] \[\alpha \in (0,1) \] \[ f:[0,1] \rightarrow \mathbb{R}\] a) Solve the weights \[\lambda_{\alpha,i} \]in dependency to \[\alpha\]so that the quadrature formula \[Q_\alpha\]is exact for every polynome of degree 2. b) For which \[\alpha \in (0,1)\]is the quadrature formula positive?
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Twaylor:
Time flies doesn't it? I tried to not be the second squeaky wheel of the household and ended up hurting myself and others severely.
clllaaaaaire:
any tips? the quality isn't the best because I am using this site on my computer
Midnight97:
Kinda a roleplay story between me and my friend enjoy... Part one Forgive me for all the screenshots.
StevenisGhost:
what type of song should I make next, and will y'all go check out my new song on
Midnight97:
My drawing sure changed over the years look at these two pictures from 2024 to no
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
Breathless:
I don't know if this would be considered art, but its close enough I believe, Any
1 day ago
12 Replies
2 Medals
2 weeks ago
2 Replies
0 Medals
2 weeks ago
2 Replies
1 Medal
1 week ago
6 Replies
2 Medals
2 weeks ago
6 Replies
1 Medal
3 weeks ago
3 Replies
0 Medals
3 weeks ago
0 Replies
0 Medals
3 weeks ago
3 Replies
0 Medals