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9/z+7=8/z-6
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\[\frac{9}{z+7}=\frac{8}{z-6}\]?
Solution: z = -1/13
\[9(z-6)=8(z+7)\] \[9z-54=8z+56\] \[9z-8z=56+54\] \[z=110\]
that is assuming it was the problem i wrote
it was 9/z+7 not 9/(z+7) i think the 7 is not under the 9
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