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20z^2=40z+60 what are the solutions of the equation?
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Solutions: z = -1 z = 3
you really know ur math, thank you
@kianap really could use some clarification on other questions
glad to help...! : )
\[20z^2 - 40z - 60z = 0\] \[20(z^2 - 2z - 3) = 0\] \[z^2 -2z -3 = 0\] \[(z-3)(z+1) =0\] Then z = 3 and z = -1 should be your solutions. you have two solutions because two values if plugged in for z would give 0, also look up factoring quadratic equations to see how I got to the last step.
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