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Simplify the equation using the properties of exponents: (x^3y^-2)^-2 (x^3y^-1)^-1 _____________ _____________ (x^-1y^3) (x^-3y^2)
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x^(-y^3 - 9y^2 + 3y)
\[1/ x^{5}y^{8}\]
\[(x ^{3y ^{-2}})^{-2}/(x ^{-y ^{3}}) . (x ^{3y ^{-1}})^{-1}/(x ^{-3y ^{2}})\] is what it looks like, right?
\[(x^{3}y^{-2})^{-2} / x^{-1}y^{3 } * (x^{3}y^{-1})^{-1} / x^{-3}y^{2} = 1/ x^{5} y^{8}\]
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