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OpenStudy (anonymous):
Evaluate the following limit: limx->0 (x-1)/(3sinx-cosx) Do not use L'Hospital's Rule
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OpenStudy (anonymous):
1
OpenStudy (anonymous):
show working please
OpenStudy (anonymous):
dont even need to solve just put the values :P
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
as neither numerator is 0 nor the denominator :P
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
thanks so much aredsani
OpenStudy (anonymous):
welcome
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