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OpenStudy (anonymous):

Evaluate the following limit: limx->0 (x-1)/(3sinx-cosx) Do not use L'Hospital's Rule

OpenStudy (anonymous):

1

OpenStudy (anonymous):

show working please

OpenStudy (anonymous):

dont even need to solve just put the values :P

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

as neither numerator is 0 nor the denominator :P

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

thanks so much aredsani

OpenStudy (anonymous):

welcome

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