Question

find the local extrema of the function

f(x)=(x^2-4)^(2/3), sketch the graph

Answer 1

well i cant sketch the graph here but tellin u the solution f'(x) = \[(2/3)2x(x ^{2}-4)^{-1/3}\]
now find y'(x)= 0 u will get 0 , -2, +2 and these are the local extemas

Answer 2

i got the same thing ok thanks i sketched the graph and check it on wolfram i got it right thanks

Answer 3

for my f'(x)=4x/3((x^2-4)^(1/3)) i multiplied it thanks aredsani!