Question

write an equation of the line containing the given point and parallel to the given line
(8,-4);6x-5y=8
the equation of the line is y=
simplify your answer in the form y=mx+b
using integers or fractions

Answer 1

5y=6x+8
y=6/5x+8/5
y=mx+b (8,-4)
-4=6/5(8)+b
-4=48/5+b
-20/5-48/5=b
-68/5 =b
y=6/5x-68/5

Answer 2

6x-5y=8
6x-8=5y
6/5*x-8/5=y
slope is 6/5
so slope of \\ line is 6/5
y=6/5*x+b
now we need y-intercept(aka b)
we know a point on the line (x=8,y=-4)
-4=6/5*8+b
-4=48/5+b
-4-48/5=b
-20/5-48/5=b
-68/5=b
so the line we are looking for is y=6/5*x-68/5

Answer 3

so the answer is y=6/5x-68/5?

Answer 4

can u give a good answer please , thank you! :)

Answer 5

i was working on it thanx

Answer 6

thank you very much! :)